db.command.aggregate.setDifference
1. Operator Description
Function: Takes two sets as input and outputs elements that exist only in the first set.
Declaration: setDifference([expression1, expression2])
2. Operator Parameters
Field | Type | Required | Description |
---|---|---|---|
- | <Array>Expression | Required | array of aggregate expressions |
3. Sample Code
Suppose the collection test
contains the following data:
{ "_id": 1, "A": [ 1, 2 ], "B": [ 1, 2 ] }
{ "_id": 2, "A": [ 1, 2 ], "B": [ 2, 1, 2 ] }
{ "_id": 3, "A": [ 1, 2 ], "B": [ 1, 2, 3 ] }
{ "_id": 4, "A": [ 1, 2 ], "B": [ 3, 1 ] }
{ "_id": 5, "A": [ 1, 2 ], "B": [ ] }
{ "_id": 6, "A": [ 1, 2 ], "B": [ {}, [] ] }
{ "_id": 7, "A": [ ], "B": [ ] }
{ "_id": 8, "A": [ ], "B": [ 1 ] }
The following code uses setDifference
to find numbers that exist only in B
:
// Sample code in the Cloud Function environment
const tcb = require('@cloudbase/node-sdk')
const app = tcb.init({
env: 'xxx'
})
const db = app.database()
const $ = db.command.aggregate
const _ = db.command
exports.main = async (event, context) => {
const res = await db
.collection('test')
.aggregate()
.project({
isBOnly: $.setDifference(['$B', '$A'])
})
.end()
console.log(res.data)
}
{ "_id": 1, "isBOnly": [] }
{ "_id": 2, "isBOnly": [3] }
{ "_id": 3, "isBOnly": [3] }
{ "_id": 4, "isBOnly": [5] }
{ "_id": 5, "isBOnly": [] }
{ "_id": 6, "isBOnly": [{}, []] }
{ "_id": 7, "isBOnly": [] }
{ "_id": 8, "isBOnly": [1] }