跳到主要内容

db.command.aggregate.setIsSubset

1. 操作符描述

功能:输入两个集合,判断第一个集合是否是第二个集合的子集。

声明:`setIsSubset([expression1, expression2])

2. 操作符参数

字段类型必填说明
-<Array>Expression聚合表达式数组

3. 示例代码

假设集合 test 存在以下数据:

{ "_id": 1, "A": [ 1, 2 ], "B": [ 1, 2 ] }
{ "_id": 2, "A": [ 1, 2 ], "B": [ 2, 1, 2 ] }
{ "_id": 3, "A": [ 1, 2 ], "B": [ 1, 2, 3 ] }
{ "_id": 4, "A": [ 1, 2 ], "B": [ 3, 1 ] }
{ "_id": 5, "A": [ 1, 2 ], "B": [ ] }
{ "_id": 6, "A": [ 1, 2 ], "B": [ {}, [] ] }
{ "_id": 7, "A": [ ], "B": [ ] }
{ "_id": 8, "A": [ ], "B": [ 1 ] }

下面的代码使用 setIsSubset,判断第一个集合是否是第二个集合的子集:

// 云函数环境下示例代码
const tcb = require('@cloudbase/node-sdk')
const app = tcb.init({
env: 'xxx'
})

const db = app.database()
const $ = db.command.aggregate
const _ = db.command

exports.main = async (event, context) => {
const res = await db
.collection('test')
.aggregate()
.project({
AisSubsetOfB: $.setIsSubset(['$A', '$B'])
})
.end()
console.log(res.data)
}
{ "_id": 1, "AisSubsetOfB": true }
{ "_id": 2, "AisSubsetOfB": true }
{ "_id": 3, "AisSubsetOfB": true }
{ "_id": 4, "AisSubsetOfB": false }
{ "_id": 5, "AisSubsetOfB": false }
{ "_id": 6, "AisSubsetOfB": false }
{ "_id": 7, "AisSubsetOfB": true }
{ "_id": 8, "AisSubsetOfB": true }