db.command.aggregate.setEquals
1. 操作符描述
功能:输入两个集合,判断两个集合中包含的元素是否相同(不考虑顺序、去重)。
声明:setEquals([expression1, expression2])
2. 操作符参数
字段 | 类型 | 必填 | 说明 |
---|---|---|---|
- | <Array>Expression | 是 | 聚合表达式数组 |
3. 示例代码
假设集合 test
存在以下数据:
{ "_id": 1, "A": [ 1, 2 ], "B": [ 1, 2 ] }
{ "_id": 2, "A": [ 1, 2 ], "B": [ 2, 1, 2 ] }
{ "_id": 3, "A": [ 1, 2 ], "B": [ 1, 2, 3 ] }
{ "_id": 4, "A": [ 1, 2 ], "B": [ 3, 1 ] }
{ "_id": 5, "A": [ 1, 2 ], "B": [ ] }
{ "_id": 6, "A": [ 1, 2 ], "B": [ {}, [] ] }
{ "_id": 7, "A": [ ], "B": [ ] }
{ "_id": 8, "A": [ ], "B": [ 1 ] }
下面的代码使用 setEquals
,判断两个集合中包含的元素是否相同:
// 云函数环境下示例代码
const tcb = require('@cloudbase/node-sdk')
const app = tcb.init({
env: 'xxx'
})
const db = app.database()
const $ = db.command.aggregate
const _ = db.command
exports.main = async (event, context) => {
const res = await db
.collection('test')
.aggregate()
.project({
sameElements: $.setEquals(['$A', '$B'])
})
.end()
console.log(res.data)
}
{ "_id": 1, "sameElements": true }
{ "_id": 2, "sameElements": true }
{ "_id": 3, "sameElements": false }
{ "_id": 4, "sameElements": false }
{ "_id": 5, "sameElements": false }
{ "_id": 6, "sameElements": false }
{ "_id": 7, "sameElements": true }
{ "_id": 8, "sameElements": false }